-2x^2-41x-119=0

Solution for -2x^2-41x-119=0 equation:

-2x^2-41x-119=0

a = -2; b = -41; c = -119;
Δ = b2-4ac
Δ = -412-4·(-2)·(-119)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-27}{2*-2}=\frac{14}{-4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+27}{2*-2}=\frac{68}{-4}
=-17
$